<div id="readability-page-1" class="page"><div><p data-ke-size="size16"><b>예제</b></p>
<pre id="code_1649515746485" data-ke-language="python" data-ke-type="codeblock"><code>mydict = {'d': 50, 'a': 20, 'b': 30, 'e': 10, 'c': 30}</code></pre>


<h3 data-ke-size="size23"><b>1. Key를 기준으로 정렬 (오름차순)</b></h3>
<pre id="code_1649515927997" data-ke-language="python" data-ke-type="codeblock"><code>mydict_sorted = sorted(mydict.items())
print(mydict_sorted)</code></pre>
<pre id="code_1649515952839" data-ke-language="python" data-ke-type="codeblock"><code>[('a', 20), ('b', 30), ('c', 30), ('d', 50), ('e', 10)]</code></pre>

<h3 data-ke-size="size23"><b>2. Key를 기준으로 정렬 (내림차순)</b></h3>
<pre id="code_1649515962173" data-ke-language="python" data-ke-type="codeblock"><code>mydict_sorted = sorted(mydict.items(), key=lambda x:x[0], reverse=True)
print(mydict_sorted)</code></pre>
<pre id="code_1649515970603" data-ke-language="python" data-ke-type="codeblock"><code>[('e', 10), ('d', 50), ('c', 30), ('b', 30), ('a', 20)]</code></pre>

<h3 data-ke-size="size23"><b>3. Value를 기준으로 정렬 (오름차순)</b></h3>
<pre id="code_1649516006099" data-ke-language="python" data-ke-type="codeblock"><code>mydict_sorted = sorted(mydict.items(), key=lambda x:x[1])
print(mydict_sorted)</code></pre>
<pre id="code_1649516014620" data-ke-language="python" data-ke-type="codeblock"><code>[('e', 10), ('a', 20), ('b', 30), ('c', 30), ('d', 50)]</code></pre>

<h3 data-ke-size="size23"><b>4. Value를 기준으로 정렬 (내림차순)</b></h3>
<pre id="code_1649516021562" data-ke-language="python" data-ke-type="codeblock"><code>mydict_sorted = sorted(mydict.items(), key=lambda x:x[1], reverse=True)
print(mydict_sorted)</code></pre>
<pre id="code_1649516028120" data-ke-language="python" data-ke-type="codeblock"><code>[('d', 50), ('b', 30), ('c', 30), ('a', 20), ('e', 10)]</code></pre>

<h3 data-ke-size="size23"><b>5. Value 기준으로 오름차순 정렬하되, Value가 같을 경우 Key는 알파벳 순서대로 출력</b></h3>
<pre id="code_1649516232890" data-ke-language="python" data-ke-type="codeblock"><code>mydict_sorted = sorted(mydict.items(), key=lambda x:(x[1], x[0]))
print(mydict_sorted)</code></pre>
<pre id="code_1649516242046" data-ke-language="python" data-ke-type="codeblock"><code>[('e', 10), ('a', 20), ('b', 30), ('c', 30), ('d', 50)]</code></pre>


<p data-ke-size="size16">복잡한 예제</p>
<pre id="code_1649517711156" data-ke-language="python" data-ke-type="codeblock"><code>mydict2 = {'d': (50, 10), 'a': (20, 30), 'b': (30, 30), 'e': (10, 20), 'c': (10, 10)}</code></pre>

<h3 data-ke-size="size23"><b>6. Value 기준으로 정렬 (오름차순)</b></h3>
<pre id="code_1649517692038" data-ke-language="python" data-ke-type="codeblock"><code>mydict2_sorted = sorted(mydict2.items(), key=lambda x:(x[1][0], x[1][1]))
print(mydict2_sorted)</code></pre>
<pre id="code_1649517742589" data-ke-language="python" data-ke-type="codeblock"><code>[('c', (10, 10)), ('e', (10, 20)), ('a', (20, 30)), ('b', (30, 30)), ('d', (50, 10))]</code></pre>



            
</div></div>

sohyunwriter

예제
mydict = {'d': 50, 'a': 20, 'b': 30, 'e': 10, 'c': 30}
 
 
1. Key를 기준으로 정렬 (오름차순)
mydict_sorted = sorted(mydict.items())
print(mydict_sorted)
[('a', 20), ('b', 30), ('c', 30), ('d', 50), ('e', 10)]
 
2. Key를 기준으로 정렬 (내림차순)
mydict_sorted = sorted(mydict.items(), key=lambda x:x[0], reverse=True)
print(mydict_sorted)
[('e', 10), ('d', 50), ('c', 30), ('b', 30), ('a', 20)]
 
3. Value를 기준으로 정렬 (오름차순)
mydict_sorted = sorted(mydict.items(), key=lambda x:x[1])
print(mydict_sorted)
[('e', 10), ('a', 20), ('b', 30), ('c', 30), ('d', 50)]
 
4. Value를 기준으로 정렬 (내림차순)
mydict_sorted = sorted(mydict.items(), key=lambda x:x[1], reverse=True)
print(mydict_sorted)
[('d', 50), ('b', 30), ('c', 30), ('a', 20), ('e', 10)]
 
5. Value 기준으로 오름차순 정렬하되, Value가 같을 경우 Key는 알파벳 순서대로 출력
mydict_sorted = sorted(mydict.items(), key=lambda x:(x[1], x[0]))
print(mydict_sorted)
[('e', 10), ('a', 20), ('b', 30), ('c', 30), ('d', 50)]
 
 
복잡한 예제
mydict2 = {'d': (50, 10), 'a': (20, 30), 'b': (30, 30), 'e': (10, 20), 'c': (10, 10)}
 
6. Value 기준으로 정렬 (오름차순)
mydict2_sorted = sorted(mydict2.items(), key=lambda x:(x[1][0], x[1][1]))
print(mydict2_sorted)
[('c', (10, 10)), ('e', (10, 20)), ('a', (20, 30)), ('b', (30, 30)), ('d', (50, 10))]

Python 딕셔너리 정렬 (Key, Value 기준 sort)

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